Model 5 Split & Fraction of work Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 21 [SSC CHSL 2015]
Janardan completes $2/3$ of his work in 10 days. Time he will take to complete $3/5$ of the same work, is
a) 6 days
b) 8 days
c) 4 days
d) 9 days
Answer »Answer: (d)
Using Rule 1,
${M_1D_1}/W_1= {M_2D_2}/W_2$
$10/{2/3} = D_2/{3/5}$
$30/2 = {5D_2}/3$
$D_2 = 30/2 × 3/5$ = 9 days
Question : 22 [SSC CGL Tier-II 2015]
Two workers A and B are engaged to do a piece of work. A working alone would take 8 hours more to complete the work than when work together. If B worked alone, would take 4$1/2$ hours more than when work together. The time required to finish the work together is
a) 4 hours
b) 5 hours
c) 6 hours
d) 8 hours
Answer »Answer: (c)
Time taken by A and B = x hours (let).
According to the question,
Time taken by A alone
= (x + 8) hours.
Time taken by B alone
= $(x + 9/2)$ hours.
$1/{x + 8} + 1/{x + {9/2}} = 1/x$
$1/{x + 8} + 2/{2x + 9} =1/x$
${2x + 9 + 2x + 16}/{(x + 8)(2x + 9)} = 1/x$
${4x + 25}/{2x^2 + 16x + 9x + 72} = 1/x$
$4x^2 + 25x = 2x^2 + 25x + 72$
$2x^2 = 72 ⇒ x^2 = 72/2 = 36$
x = $√{36}$ = 6 hours
Question : 23 [SSC CGL Prelim 2005]
A does $7/10$ part of work in 15 days. After that he completes the remaining work in 4 days with the help of B. In how many days will A and B together do the same work ?
a) 12$2/3$ days
b) 10$1/3$ days
c) 8$1/4$ days
d) 13$1/3$ days
Answer »Answer: (d)
Using Rule 2,
Remaining work = $1 - 7/10 = 3/10$
(A + B) take 4 days to do $3/10$ work
(A + B) will do the work in $4 × 10/3$ days
= $40/3 =13{1}/3$ days
Question : 24 [SSC CGL Tier-II 2015]
A company employed 200 workers to complete a certain work in 150 days. If only one fourth of the work has been done in 50 days, then in order to complete the whole work in time, the number of additional workers to be employed was
a) 300
b) 100
c) 200
d) 600
Answer »Answer: (b)
Using Rule 1,
200 workers do $1/4$ work in 50 days.
How many workers will do $3/4$ work in 100 days ?
Number of additional workers = x (let)
${M_1D_1}/W_1 = {M_2D_2}/W_2$
${200 × 50}/{1/4} = {(200 + x) × 100}/{3/4}$
(200 + x) 100 = 3 × 200 × 50
200 + x = 300
x = 300 - 200 = 100
Question : 25 [SSC CPO S.I.2003]
A can complete a work in 6 days while B can complete the same work in 12 days. If they work together and complete it, the portion of the work done by A is
a) $2/3$
b) $1/3$
c) $1/2$
d) $1/4$
Answer »Answer: (a)
Using Rule 2,
Time taken by A and B
= ${6 × 12}/{6 + 12} = {6 × 12}/18 = 4$
Work done by A in 4 days = $4/6 = 2/3$
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Model 5 Split & Fraction of work Shortcuts »
Click to Read...Model 5 Split & Fraction of work Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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